-y^2+20y-100=0

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Solution for -y^2+20y-100=0 equation: 



-y^2+20y-100=0

We add all the numbers together, and all the variables

-1y^2+20y-100=0

a = -1; b = 20; c = -100;
Δ = b2-4ac
Δ = 202-4·(-1)·(-100)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{-20}{-2}=+10$

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